Question

If 5 sin 0 - 12 cos 0 = 0 then find the value of sec 0.​

Answer 1

5Sin A - 12cos A =0

5Sin A = 12 cos A

5/12= cos A /sin A

5/12= cot A

12/5 = tan A

12---> perpendicular

5---> Base

using Pythagoras theorem

P^2+B^2=H^2

144+25=H^2

169=H^2

Hypotenuse = 13

sec A = Hypotenuse / Base

sec A = 13/5

Answer 2

Answer:

Consider theta = @

5sin@-12cos@=0

Divide by cos@

=> 5Sin@-12cos@=0 (cos@ cancel out)

Cos@ Cos@

=>5×tan@-12=0

=>5tan@=12

Square on both sides

(consider * = square^2)

=>25tan*@= 144

=>tan*@= 144/25

=>sec*@ -1 = 144/25 (tan*@=sec*@-1)

=>sec*@=144/25 - 1

=>sec*@= 169/25

=>sec@= 13/5