Question

) If 5 sin 0 - 12 cos 0 = 0 then find the value of sec 0.​

Answer 1

Answer:

$\frac{13}{5}$

Step-by-step explanation:

$5sin(θ)-12cos(θ)=0 \\ 5sin(θ)=12cos(θ) \\ \frac{sin(θ)}{cos(θ)} = \frac{12}{5} \\ tan(θ)= \frac{12}{5} \\ now sec²(θ) - tan²(θ)=1 \\ sec²(θ)=1+tan²(θ) \\ sec²(θ)=1+( \frac{12}{5}) ^{2} \\ sec²(θ)=1+( \frac{144}{25} ) \\ sec²(θ)= \frac{25+144}{25} \\ sec²(θ)= \frac{169}{25} \\ sec(θ)= \frac{13}{5}$