If 5 sin 0 = 3, find the value of sec 0 - tan 0/sec 0+tan 0
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Answer:
1/4
Step-by-step explanation:
sinO=3/5
:cosO=4/5(by pithogorus theorem)
secO=5/4(reciprocal cosO)
therefore secO-tanO/secO+tanO=
=5/4-(3/5÷4/5)/5/4+(3/5÷4/5)
=(5/4-3/4)÷(5/4+3/4)
=(2/4)÷(8/4)
=(1/2)÷(2/1)
=1/4
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