if 5 sin 0 -7 cos0=0 then find the sec0
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Answered by
1
5 sin0 = 7cos0
Hence
5 tan0 = 7 (because we divide by cos0 both sides)
tan0 = 7/5
Using formula,
tan^20 + 1 = sec^2
49 + 25 = 25 sec^20
sec0 = √74 / 5
Hence
5 tan0 = 7 (because we divide by cos0 both sides)
tan0 = 7/5
Using formula,
tan^20 + 1 = sec^2
49 + 25 = 25 sec^20
sec0 = √74 / 5
Answered by
2
you need to learn trigonometry identities from your book
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