If 5 . sin – 12. cos = 0 Find the value
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0
5cosθ−12sinθ=0
⇒5cosθ=12sinθ
⇒cotθ=
5
12
⇒
2cosθ−sinθ
sinθ+cosθ
=
sinθ(2cotθ−1)
sinθ(1+cotθ)
=
2×
5
12
−1
1+
5
12
=
5
24
−1
5
17
=
5
24−5
5
17
=
5
17
×
19
5
=
19
17
Hence, the answer is
19
17
.
Answered by
0
Answer: =
Step-by-step explanation:
5sinθ - 12cosθ = 0
5sinθ = 12cosθ
sinθ/cosθ = 12/5
tanθ=12/5
opp/adj = 12/5
a² + b² = c² (Pythagoras)
12² + 5² = c²
144 + 25 = c²
c² = 169
c = 13
opp = 12 adj = 5 hypo = 13
sinθ = 12/13 cosθ= 5/13
sinθ+cosθ = 12/13 + 5/13 = 17/13
sinθ - cosθ = 12/13 - 5/13 = 7/13
=
=
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