if 5 sin A = 3. find the value of cosA and tan A
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5 sin A = 3
=> sinA = 3/5 = perpendicular/hypotenuse
by Pythagoras theorem,
=> (h)^2 = (p)^2 + (b)^2
=> (5)^2 = (3)^2 + (b)^2
=> 25 - 9 = (b)^2
=> √16 = b
=> b = 4
now,
cos A = base/ hypotenuse
=> cos A = 4/5
and
tan A = perpendicular/base
=> tan A= 3/4
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