Question

If 5 sin A=3 then find 3sinA+tanA-2 secA​

Answer 1

Answer:

Given:- 3sinA = 5sinB.

or, sinA/sinB = 5/3.

Applying componedo & devidendo.

or, (sinA + sinB)/(sinA - sinB) = (5+3)/(5–3).

or, {2.sin(A+B)/2.cos(A-B)/2}/{2.cos(A+B)/2.sin(A-B)/2} = 8/2.

or, tan(A+B)/2. cot(A-B)/2 = 4.

or, tan(A/2+B/2)/tan(A/2-B/2) = 4. Answer

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