If 5 Sin A + Cos square A = 2 and A is an acute angle, find the value of SinA
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Answer:
5sinA + cos²A = 2
or, 5sinA = 2 - cos²A
or, 5sinA = 1 + 1 - cos²A
or, 5sinA = 1 + sin²A
or, 5 = 1 + sin²A/sinA
or, 1/sinA + sin²A/sinA = 5
or, cosecA + sinA = 5
or, sinA = 5 - cosecA
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