if 5 sin theta =3 find the value of sec theta - tan theta by sec theta + tan theta
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5sinθ = 3
=> sin θ = 3/5
=> θ= 37°
So cos 37° = 4/5
So tan 37° = sin 37°/ cos 37° = (3/5)/(4/5)= 3/4
and sec 37° = 1/cos 37° = 1/(4/5)= 5/4
(sec 37°- tan 37°)/(sec 37°+ tan 37°) = {(5/4)-(3/4)}/{(5/4)+(3/4)} = (1/2)/2 = 1/4
!! Jai shree ram !!
=> sin θ = 3/5
=> θ= 37°
So cos 37° = 4/5
So tan 37° = sin 37°/ cos 37° = (3/5)/(4/5)= 3/4
and sec 37° = 1/cos 37° = 1/(4/5)= 5/4
(sec 37°- tan 37°)/(sec 37°+ tan 37°) = {(5/4)-(3/4)}/{(5/4)+(3/4)} = (1/2)/2 = 1/4
!! Jai shree ram !!
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