Question

If 5 sin theta =3,then find cos theta , tan theta, sec theta-cosec theta

Answer 1

Answer:

ɡiven that

5sinθ=3,sinθ=3/5

cosθ=?

tanθ=?

secθ-cosecθ=?

now as we know that,

${ \sin}^{2} θ + { \cos }^{2} θ = 1 \\ \frac{9}{25} + { \cos }^{2} θ = 1 \\ { \cos}^{2} θ = \frac{16}{25} \\ \cosθ = \frac{4}{5}$

$\tanθ = \frac{ \sin θ}{ \cosθ } \\ = \frac{ \frac{3}{5} }{ \frac{4}{5} } \\ = \frac{3}{4}$

$\secθ - \cosecθ = \frac{1}{ \cos θ} - \frac{1}{ \sin θ} \\ = \frac{5}{4} - \frac{5}{3} \\ \frac{ - 5}{12}$

this is you answer

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Answer 2

Answer:

Hope it helps!!

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