Question

if 5 sin tita -12 cos tita =0 then find the value of sec tita​

Answer 1

Answer:

sec tita =13÷5

Step-by-step explanation:

i am considering tita as A

now look

5sinA=12cosA

sinA÷cosA=12÷5

tanA=12÷5

tan^2A=12^2÷5^2

sec^2A-1=144÷25

sec^2A=144÷25+1

sec^2A=169÷25

secA =13÷5