Question

if 5 sinA=3 find sin^2-cos^2​

Answer 1

Step-by-step explanation:

5 sin A=3

we can write it as sin A =3/5

By Pythagoras theorem:

H^2=P^2+B^2

5^2= 3^2+B^2

25-9=B^2

B= √16

= 4

sin^2-cos^2

(3/5)²- (4/5)²

9/25-16/25

(9-16)/25

-5/25

=-1/5

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