if 5 tan =3 ,then what is the value of (5sin-3cos/ 4sin+3cos)
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Answer:
3tan=5
tan=5/3
P=5 ,B=3
let find H by pythagoras theory
H^2=P^2+B^2
=(5×5) +(3×3)
=25+9
=34
H^2=34
H=√34
sin=p/h=5/√34
cos=b/h=3/√34
5sin-3cos / 4sin+3cos
put the values u will get rhe answer.
5×5/√34 -3×3/√34 / 4×5/√34+3×3/√34
=25-9/√34/20+9/√34
=25-9/20+9
=16 /29
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