Question

If 5 tan A = 4, find the value of<br />sin A -3 cos A / 8sinA + 2 cos A (with steps). Please answer only if it is genuine.​

Answer 1

Answer:

$tan \: a = \frac{4}{5} \\ sin \: a \: = \frac{4}{ \sqrt{41} } \: \: and \: \: \: cos \: a = \frac{5}{ \sqrt{41} } \\ now \: \: \: \frac{sin \: a \: - 3cos \: a}{8sin \: a - 2cos \: a} = \\ \frac{ \frac{4}{ \sqrt{41} } - \frac{15}{ \sqrt{41} } }{ \frac{32}{ \sqrt{41} } - \frac{10}{ \sqrt{41} } } = \frac{4 - 15}{ \sqrt{41} } \times \frac{ \sqrt{41} }{32 - 10} = \\ - \frac{11}{22} = - \frac{1}{2} \: \: ans.$