If 5 Tan alpha = 4, show that 5 Sin alpha - 3 Cos alpha / 5 Sin alpha + 2 Cos alpha = 1/6
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We have,
5 tan α⇒tanα=54
Now, 5sinα+2cosα5sinα−3cosα
=cosα5sinα+2cosαcosα5sinα−3cosα
=cosα5sinα+cosα2cosαcosα5sinα−cosα3cosα
=5tan,α+25tan,α−3
=5×54+25×54−3
=4+24−
=1/6
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