If 5 tan theta =4,then the value of 5 sin theta-4 cos theta/5 sin theta +4 cos theta is
shreyans13:
I think the ans is zero
Answers
Answered by
35
let theta be A
given
5 tanA = 4
tanA = 4/5
Sin A / Cos A = 4/5 (Tan A = Sin A/CosA)
Sin A = 4x and Cos A = 5x (x is constant)
now
(5 Sin A - 4 Cos A)/(5 Sin A + 4 Cos A)
= [5 × 4x - (4 × 5x)]/[ 5 × 4x + (4 × 5x)]
= [20x - 20x]/ [20x + 20x]
= 0/40x
Ans. 0
given
5 tanA = 4
tanA = 4/5
Sin A / Cos A = 4/5 (Tan A = Sin A/CosA)
Sin A = 4x and Cos A = 5x (x is constant)
now
(5 Sin A - 4 Cos A)/(5 Sin A + 4 Cos A)
= [5 × 4x - (4 × 5x)]/[ 5 × 4x + (4 × 5x)]
= [20x - 20x]/ [20x + 20x]
= 0/40x
Ans. 0
Answered by
15
if u don't want to waste your time then simply put 5sin(A)=4cos(A) into ur equation then u will get upper term as zero.
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