Question

If 5 tan tita =4 find the value of 5 sin tita-3 cos tita /5 sin tita +2 cos tita ​

Answer 1

Answer:

Given5tanθ=4orcosθsinθ=54∴sinθ=54cosθThegiventrigonometricexpressionis→5sinθ+2cosθ5sinθ−3cosθ(Substitutingsinθ=54cosθ)=5×54cosθ+2cosθ5×54cosθ−3cosθ=4+24−3=61

Step-by-step explanation:

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