Question

if 5 tan0 = 12, find 13 sin 0 / 3

Answer 1

Answer:

tan0 = 12/5 = P/B

by Pythagoras

H^2 = 144+25

= 169

H = 13

sin0 = P/H

= 12/13

ATQ

13*12/13/3

12/3

= 4

hope it will help you

Answer 2

Answer:

4

Step-by-step explanation:

5Tanθ = 12

Tanθ = 12/5.

Tanθ = Height (Opposite side to θ) / Base.

Find Hypotenuse when Base = 5, height = 12.

Since this is a right angled triangle, using Pythagoras theorem.

Height² + Base² = Hypotenuse²

144 + 25 = Hypotenuse²

Hypotenuse = √169 = 13.

Sinθ = Height / Hypotenuse = 12/13

13/3 Sinθ = 13/3 * 12/13 = 4.