if 5 tan0 =4 find the value of 5 sin0 _ 3 cos0 / 5 sin0 + 2 cos 0
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5tanФ = 4
tanФ = 4/5
find 5sinФ - (3cosФ)/(5sinФ) + 2cosФ
If it is correct, the answer is below....
5sinФ + 2cosФ - (3/5)tanФ →(1)
tanФ = 4/5
⇒ tan²Ф = 16/25
⇒sec²Ф - 1 = 16/25
⇒sec²Ф = 41/25
⇒secФ = √(41)/5
⇒cosФ = 5/√41
sinФ = tanФcosФ
sinФ = 4/5 x 5/√41
⇒sinФ = 4/√41
Substitution in (1)
5(4/√41) + 2(5/√41) - (3/5)(4/5)
= 20/√41 + 10/√41 - 12/25
= 30/√41 - 12/25
I think this is the answer
long hours of typing.
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