If 5(tan2 x – cos2x) = 2 cos 2x + 9, then the value of cos 4x is
-3/5
1/3
2/9
-7/9
Answers
Answered by
2
Answer:
♠ The correct option is D
Explanation:
5(sec2 x – 1 – cos2 x) = 2(2cos2 x – 1) + 9
Let cos2 x = t
5(1/t - 1 - t) = 2(2t - 1) + 9
5(1 – t – t2) = 4t2 + 7t
9t2 + 12t – 5 = 0
t = 1/3, -5/3
cos2 x = 1/3
cos 2x = 2/3 - 1 = -1/3
➾ cos 4x = -7/9
Answered by
0
Answer:
Explanation:
The correct option is D
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