Question

if 5 tanA = 4 ,then the value of 5SinA-3cosA /sinA+2cosA is​

Answer 1

Answer:

tan A = 4/5 = p/b

h=√4²+5+

=√16+25

=√41

5sinA-3cosA/5sinA+2cosA =5×4/√41-3x5/√41/5x4/√41+ 2x5/√41 = 5/√41 x √41/30

= 20/√41-15/41/20/√41+10/√41 =20-15/√41 ÷ 20+10/√41

= 5/30

=1/6

Answer 2

Answer:

Refers to the above attachment

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