If 5 tane = 4, then
5sin 0 - 3cos e
sin 0 +2 coso
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Step-by-step explanation:
ANSWER
Divide the numerator and denomenator by cosθ
cosθ
5sinθ+2cosθ
cosθ
5sinθ−3cosθ
⇒
cosθ
5sinθ
+
cosθ
2cosθ
3cosθ
5sinθ
−
cosθ
3cosθ
⇒
5tanθ+2
5tanθ−3
Substituting the value of 5tanθ, we get
⇒
4+2
4−3
=
6
1
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