if 5 times the 5th term of an A.P is equal to the 8times its 8th term shows that its 13th term is zero
OR
if the nth term of an A.P is 7-3n,find the sum of twenty five terms
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5(a + 4d) = 8(8 + 7d)
5a + 20d = 8a + 56d
8a - 5a = 20d - 56d
3a = - 36d
a = - 12d
a + 12d = 0
Thus 13th term is 0
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5a + 20d = 8a + 56d
8a - 5a = 20d - 56d
3a = - 36d
a = - 12d
a + 12d = 0
Thus 13th term is 0
Hope it helps.
Mark me as brainlist!!
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Answered by
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Answer:
Step-by-step explanation:
Let the first term of the A.P.=
a and common difference =d
5×5Tth term=8×8Tth term
5(a+(5-1)d)=8{a+(8-1)d}
5a+20d=8a+56d
8a-5a+56d-20d=0
3a+36d=0
3a=-36d
a=-12d
13th term
=a+(13-1)d
=-12d+12d
=0
nth term
=7-3n
Put n=1,2,3,4,.........
A.P 4,1,-2,.......
a=4
d=1-4=-3
Sn=n/2[2a+(n-1)d]
=5/2[2×4+(5-1)×-3]
=5/2(8-12)
=5/2×-4
=5×-2
=-10
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