If 5(x-3)·3(2x-8)=225
Find the value of x
Please note that (x-3) and (2x-8) are powers of 5 and 3 respt.
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This is an easy question. We know RHS=5^2.3^2 and LHS=5^(x-3).3^(2x-8)
Now, Comparing the powers of 5 and 3, we get
x-3=2 and 2x-8=2
Equating RHS, 2x-8=x-3 So x=5
Now, Comparing the powers of 5 and 3, we get
x-3=2 and 2x-8=2
Equating RHS, 2x-8=x-3 So x=5
chandraharish:
Thanks
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