Question

if 5^x 3^y=225 x 405 find the value of x^(2y-3x)​

Answer 1

Answer:

27

Explanation:

225 = 5 X 5 3 X 3

225 = 5 X 5 3 X 3405 = 3 X 3 X 3 X 3 X 5

225 = 5 X 5 3 X 3405 = 3 X 3 X 3 X 3 X 5225 X 405 = 3^6 X 5^3

225 = 5 X 5 3 X 3405 = 3 X 3 X 3 X 3 X 5225 X 405 = 3^6 X 5^3x = 3, y= 6

225 = 5 X 5 3 X 3405 = 3 X 3 X 3 X 3 X 5225 X 405 = 3^6 X 5^3x = 3, y= 6Putting values , x^(2y-3x) = 27

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Answer 2

Answer:

27

Explanation:

Firstly multiply 225&405 then equal to 91125

Then, find the LCM of 91125

That is 5^3 and 3^6

X=3, y=6

Put the value in equation

x^2y-3x

x^2*6-3*3 'x to the power of 2y-3x

27 Ans