If 5 x is equal to sec theta and 5 by x is equal to tan theta find the value of 5 x 5 into x square minus 1 by x square
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sec²θ - tan²θ = 1
=> (5x)² - (5/x)² = 1
=> 25x² - 25/x² = 1
=> 25 ( x² - 1/x² ) = 1
=> 5 x 5 ( x² - 1/x² ) = 1
=> 5 x ( x² - 1/x² ) = 1/5.
=> (5x)² - (5/x)² = 1
=> 25x² - 25/x² = 1
=> 25 ( x² - 1/x² ) = 1
=> 5 x 5 ( x² - 1/x² ) = 1
=> 5 x ( x² - 1/x² ) = 1/5.
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