Question

if 5,x,y,14 are in arthematic progression then the value of y is?
a.11
b.8
c.22
d.16​

Answer 1

Answer:

5,8,11,14

8-5=11-8=14-11

3=3=3=

so, y=11

Answer 2

Answer:

The value of y is 9.

Step-by-step explanation:

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

In AP,  main terms:

First term (a)

Common difference (d)

nth Term ($a_{n}$)

Sum of the first n terms ($S_{n}$)

All three terms represent the property of Arithmetic Progression.

The formula for finding the n-th term of an AP is:

$a_{n} =a+(n-1)d$

Given: Sequence $5,x,y,11$

here $a=5$

Now,

$a_{4}=a+(4-1)d\\ a_{4}=a+3d$

$11=5+3d\\3d=11-5\\3d=6\\d=2$

Since, being it's an Arithmetic Progression so difference between all numbers is constant which is 2.

Hence, series is 5,7,9,11.

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