Question

If  5^x3^y= 225 x 405, find the value of x^2y-3x ​

Answer 1

Given :   $5^x.3^y=225 \times 405$

To Find :   $x^{2y-3x}$

a. 27

b. 81

c. 125

d. 25

Solution:

$5^x.3^y=225 \times 405$

225 = 3 * 3 * 5 * 5  = 3² * 5²

405 = 3 * 3 * 3 * 3 * 5 = 3⁴ * 5¹

225 * 405  = 3² * 5² * 3⁴ * 5¹

xᵃ * xᵇ = xᵃ⁺ᵇ

= 3²⁺⁴ * 5²⁺¹

= 3⁶ * 5³

= 5³ * 3⁶

Equate with $5^x.3^y$

x = 3  and y = 6

2y - 3x

= 2 (6) - 3(3)

= 12 - 9

= 3

$x^{2y-3x}$

= 3³

= 27

Hence Correct option is  a. 27

Learn More:

how many laws of exponents​ - Brainly.in

https://brainly.in/question/35990488

0.243^0.2×10^0.6=? Pls help me it's very urgent - Brainly.in

brainly.in/question/3246219

3⁴)² ÷ [3⁴ X 3⁵] : Evaluate.

brainly.in/question/5030040

Answer 2

Answer:

Step-by-step explanation: