if 5^y=1 then value of y is
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Answer:
∣y∣=x−1
since ∣y∣ is always positive
x−1 will always be a positive number
That means x is always greater than equal to 1
so now the equations become
x+2+y=5...(1)
x−y=1...(2)
solving (1) and (2) we get,
x=2 and y=1
⇒x+y=2+1=3
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