Question

If 50 g of common salt is added to 150 g of water at 20 °C, how many grams of common salt will remain undissolved in the water?

Answer 1

The amount of undissolved salt remain in water is 3.55 grams.

Explanation:

The saturation point describes a point in water where the water cannot hold any more of a particular chemical, causing any extra material to remain suspended in the pool water.

Solubility indicates the maximum amount of a substance that can be dissolved in a solvent at a given temperature. Such a solution is called saturated. Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g.

Likely, the Saturation point depends upon the temperature. Generally, the saturation point of salt in one litre of water is 357grams.

If 50 grams of salt added in 150grams of water is the remaining amount of salt according to saturation point.

= 357× 150÷ (1000)

=53.55grams of salt.

If 50 grams are dissolved, the remaining 3.55grams of salt are unsaturated.