If 50 gram of each methane & SO2 is enclosed in container exerting 1.5 atm total pressure. what is methane to SO2 mole fraction ratio?
correct answer is 4:1 how?solve it direct answer is not acceptable
Answers
Answered by
26
Explanation:
Let us take x gm of each of the components.
Molecular Mass of SO
2
=64
∴ moles of SO
2
=
64
x
Molecular Mass of CH
4
=16
∴ moles of CH
4
=
16
x
Molecular Mass of O
2
=32
∴ moles of O
2
=
32
x
Total Moles =
64
x
+
16
x
+
32
x
=
64
7x
Mole fraction of CH
4
=
7x/64
x/16
=
7
4
Hence, partial pressure of CH
4
= mole fraction × total pressure =
7
4
×2.1=1.2 atm
Answered by
1
Answer:
zaq find the puzzle
Similar questions