Question

if 50 gram of sodium react with chlorine to form an 26 gram of fault how many gram of chlorine reacted

Answer 1

Hey there !

Thanks for the question !

Answer:

This can be solved by the method of Stoichiometric equations.

Now let us write the balanced equation for the formation of salt  in the above case.

2Na + Cl₂ => 2 NaCl

=> 2 moles of Na + 1 mole of chlorine gas gives 2 moles of NaCl.

According to the question,

26 grams of NaCl is formed.

=> Number of moles of NaCl formed = 26 g / 58 g

=> Number of Moles = 0.4 moles

So,

1 mole of Cl₂ => 2 moles of NaCl :: x moles of Cl₂ => 0.4 moles of NaCl

Product of Means = Product of Extremes

=> 1 × 0.4 = 2 × 'x'

=> x = 0.4 / 2 = 0.2 moles

So 0.2 moles of Chlorine gas reacts with 0.4 moles of NaCl.

In terms of mass, 0.2 moles of Chlorine = 0.2 × 35.5 = 7.1 g

Hence 7.1 grams will react to form 26 grams of NaCl.

Hope my answer helped !