Question

If 50 joule of heat is produced in in each second in a 2 ohm resistor.find this potential difference across the resistor​

Answer 1

Explanation:

Heat = I^2Rt

50 J = I²× 2 ×1

50J = 2I²

I²= 50 / 2

I² = 25

I = root under 25

I = 5 A

So current is 5 Ampere .

Potential difference i.e, V = IR

V = 5 × 2 = 10 volt

Answer 2

✬ Potential Difference = 10 V ✬

Explanation:

Given:

• Heat given is 50 J.
• Time is 1 second.
• Resistance is 2 ohms.

To Find:

• What is the potential difference ?

Formula to be used:

• H = I²RT
• V = IR

Solution: We have

• H = 50 J
• I = ?
• R = 2 ohns
• T = 1 second

Put the values in the formula

$\implies{\rm }$ H = I²RT

$\implies{\rm }$ 50 = I² × 2 × 1

$\implies{\rm }$ 50/2 = I²

$\implies{\rm }$ 25 = I²

$\implies{\rm }$ √25 = I

$\implies{\rm }$ √5 × 5 = I

$\implies{\rm }$ 5 = I

So current is 5 A.

Now we have

• V = ?
• I = 5 A
• R = 2 ohms

Putting the values in second formula

$\implies{\rm }$ V = IR

$\implies{\rm }$ V = 5 × 2

$\implies{\rm }$ V = 10 V

Hence, potential difference is 10 volts.