Question

If 50 kg of fine aggregates and 100 kg
of coarse agregates are mixed in a concrete
whose water cement ratio is 0.6, the weight of
water required for harsh mix, is
​

Answer 1

your answer is 12kg

I think it will help you

Answer 2

Answer: C

Explanation:

step by step solution:

for harsh mix concrete:

weight of water required= (0.3xweight of fine agg + 0.05xweight of coarse agg.)x water-cement ratio

= (0.3x50+0.05x100)x0.6

=12 kg