Question

If 50 m is the distance at which a car can be stopped when initially it was moving with speed 10ms, ther
making the speed of the car 50ms, the distance at which the car can be stopped is :
(a) 250 m
(b) 500 m
(c) 1000 m
(d) 1250 m​

Answer 1

Answer:d) 1250

Explanation:

In first case,

u=10m/s

v=0

s=50m

So, a=(v.v-u.u)/2s= (0*0-10*10)/2*50=(0-100)/100=-100/100=-1m/s sq

In second case,

u=50m/s

v=0

a=-1m/s sq.

So, s=(v.v-u.u)/2a=(0*0-50*50)/2*(-1)=(0-2500)/-2=(-2500/-2=1250m/s.

Please mark it as a brainly answer.