Question

If 50 men can do two thirds of a piece of work in 30 days then how much work can be done by 45 men in 20 days​

Answer 1

Answer:

$\frac{2}{5}$ of a piece of work can be done by 45 men in 20 days.

Step-by-step explanation:

In order to solve this problem, the following formula is required.

m₁d₁t₁w₂ = m₂d₂t₂w₁

where, m₁, m₂ = number of men.

d₁, d₂ = number of days required.

t₁, t₂ = amount of time required, in hr, min or sec. (if mentioned)

w₁, w₂ = work done.

• NOTE: The left hand side of the formula contains w₂ and the right hand side contains w₁, unlike the m,d or t.

Thus, in the given question, we can see that,

• m₁ = 50 men, d₁ = 30 days, w₁ = $\frac{2}{3}$
• m₂ = 45 men, d₂ = 20 days, w₂ = ?

Let w₂ = x.

Using the above values in the formula, we have,

50 * 30 * x = 45 * 20 * $\frac{2}{3}$

⇒ $x = \frac{45 * 20 * 2}{3* 50 * 30}$

⇒$x= \frac{3* 20 * 2}{3 * 50 * 2}$

⇒$x= \frac{20}{50}$

⇒$x=\frac{2}{5}$

Thus, in 20 days, 45 men can complete $\frac{2}{5}$ of the work.