Question

if 50% of acetic acid dimerises in a solvent and rest ionises then it's vann hoffs factor is
1)1
2)1.25
3)0.75
4)2​

Answer 1

Answer:

The van't hoff factor when 50% of acetic acid dimerises in a solvent and rest ionises will be option 3)0.75

Explanation:

Van't Hoff factor is defined as the ratio of number of particles after association to the number of particles before association.

Mathematically, it is given as,

i = (1-α) + α/n

α = 50% = 0.5

n = 2 for acetic acid

hence

i = (1 - 0.5) + (0.5/2)

= 1 - 0.5 + 0.25

=> i = 0.75

Hence the van't hoff factor when 50% of acetic acid dimerises in a solvent and rest ionises will be option 3)0.75