Question

If 50% of the drug dissolve in 12 mins how long will take to dissolve 80% of the drug

Answer 1

Answer:

ok

Explanation:

it takes 2.4 mins for 10%

so for 80% 2.4×8= 19.2 minutes.

hope u understood. brother.

or another method first find out for 100 percentage. For 50 it is 12 means 100 will be 12+12 =24.

So for 10% 24÷by 10 So 2.4 .

happy and glad to help

Answer 2

The answer is 19.2 mins.

Given: 50% of the drug dissolves in 12 mins.

To Find: how much time it will take to dissolve 80% of the drug?

Solution:

Time is taken to dissolve 50% of the drug = 12 mins

Time is taken to dissolve 1% of drug = $\frac{12}{50}$ mins

∴ Time is taken to dissolve 80% of the drug = $\frac{12}{50} \times 80$mins

                                                                         = $\frac{12 \times 8}{5}$ mins

                                                                         = $\frac{96}{5}$ mins

                                                                         = 19.2 mins

Answer) It will take 19.2 minutes to dissolve 80% of the drug.

Unitary Method

• In the given question, we need to use the unitary method to solve the question. The unitary method refers to the usage of a single entity to solve a larger quantity of substances.

• Since it takes 12 minutes to dissolve 50% of the drug, it will surely take less time to dissolve 1% of the drug. Thus, the numbers have been divided to find the time for the dissolving of a single entity.

• Now when we know the time of a single entity, we can multiply it by 80 to calculate the time required for the dissolving of 80% of the drug.

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