If 50% of (x-y)=30% of (x+y),then what percent of 'x' is 'y' ?
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50/100 × (x-y) = 30/100 × (x+y)
(x-y)/2 = 3(x+y)/10
cross multiplying,
10(x-y) = 2[3(x+y)]
10x - 10y = 2(3x + 3y)
10x - 10y = 6x +6y
10x - 6x = 6y + 10y
4x = 16y
x= 4y
Hope this helps you:)
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