If 500 ml of N\30 HCl solution mixed with
800 ml of N\30 NaOH solution, the nature and normality of solution are
(1) Basic, .0026 N
(2) Acidic, 0.0026 N
(3) Acidic, 0.001 N
(4) Basic, 0.01 N
Answers
Answered by
1
Answer:
basic .0026N
Explanation:
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Answered by
0
Answer:
Mole = concentration x volume
mole of NaOH = 50ml x 0.2 = 10.0
mole of HCl = 50ml x 0.4= 20.0
10 mole of NaOH exactly neutralized by 10 mole of HCl.
NaOH + HCl = NaCl + H2O
that is 20 -10 = 10 HCl mole
Con of H+ = no of mole of H+ / total volume of solution (50+50 ml = 100 ml)
= 10/100 = 0.1
pH = log ( H+)
= log (0.1) = 1
s0 the pH of solution will be one(1) .
Explanation:
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