Question

if 500 ml of n/30 hcl solution mixed with 800ml of n/40 naoh solution then find the normality and nature of solution​

Answer 1

N1 = 1/30

V1 = 500ml = 0.5L

N2 = 1/40

V2 = 800ml = 0.8L

N1 x V1 + N2 x V2 = N3 x V1 + V2

1/30 x 0.5 + 1/40 x 0.8 = N3 x 1.3

0.02 + 0.02 = N3 x 1.3

N3 = 0.04/1.3 = 0.03

N1 > N2

the nature of solution is acidic