Question

if 500gm of ice at 0°C temperature is melted to water at 0°C , calculate the heat energy for this change (given latent heat of fusion of ice is 80 cal/gm)​

Answer 1

Given

• Mass of ice = 500 gm
• Initial Temperature = 0°C
• Final Temperature = 0°C
• Leaten heat of ice = 80 cal/g

To Find

• The amount of heat required

Solution

☯ Q₁ = mL

☯ Q₂ = mC∆T

• Their sum would be equal to the net heat energy required for the ice to melt

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✭ According to the Question :

➞ Q = Q₁ + Q₂

➞ Q = mL + mC∆T

➞ Q = (0.5 × 80) + (0.5 × 1 × [0-0])

➞ Q = 40 + 0

➞ Q = 40 J

∴ The amount of heat energy required to melt the ice is 40 J

Answer 2

Answer:

Given :-

if 500gm of ice at 0°C temperature is melted to water at 0°C ,

To Find :-

Heat energy

Solution :-

We know that

1 kg = 1000 g

500 g = 500/1000 = 0.5 kg

Heat energy for first case

= 0.5 × 80

= 40 J

For second case.

= 0.5 × 1 × (0 - 0)

= 0.5 × 1 × 0

= 0 J

Now

The total heat energy is 40 + 0 = 40 Joules