Question

If 50KN load is applied on steel rod of cross-section area 400mm², stress will be___?

A. 120 Mpa

B. 140 Mpa

C. 125 MPa

D. 130 Mpa​

Answer 1

stress = force / area

$400mm ^{2} = \: 400x1 }^ {10}^{ - 6} {m}^{2}$

force = 500× 10^3 /400×10^-6

=1.25 ×10^9

= 125 MPa