If 51y3 is a multiple of 9, where y is a digit, what is the value of y?
Answers
Answered by
4
Answer:
5+1+y+3=9
9+y=9
y=9-9
=0
Answered by
6
Step-by-step explanation:
We take any number at this place of y .
when a digit will be given it will be divisible by 9 when it's sum is equal to 9' s table .
we take example :- 396 = 3+9+6 = 18
18 is the multiple of 9 so this digit is divisible by nine.
51y3 = 5 + 1+ _+ 3 = 9
We take 0 or 9 at this place
5+1+0+3 = 9
so , this digit is divisible by 9
5103 ÷ 9 = 567
Similar questions