Math, asked by vaishalinivaishu05, 7 months ago

If 51y3 is a multiple of 9, where y is a digit, what is the value of y?​

Answers

Answered by stutiray40
4

Answer:

5+1+y+3=9

9+y=9

y=9-9

=0

Answered by virenderyadav9694286
6

Step-by-step explanation:

We take any number at this place of y .

when a digit will be given it will be divisible by 9 when it's sum is equal to 9' s table .

we take example :- 396 = 3+9+6 = 18

18 is the multiple of 9 so this digit is divisible by nine.

51y3 = 5 + 1+ _+ 3 = 9

We take 0 or 9 at this place

5+1+0+3 = 9

so , this digit is divisible by 9

5103 ÷ 9 = 567

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