if 51z3 is a multiple of 3 where Z is a digit what might be the values of Z
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add the digits 5,1,3,z
which comes=5+1+3+z
=9+z
now as we know the divisibility test of 3 is that "the individual digits of the number add up to be a multiple of 3."
since the digits add up to 9+z ,
then z can be that number which adds to 9 and forms a multiple of 3.
Hence , z can be 0,3,6 or 9....
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