if 52 men can do a piece of work in 35 days. In how many days will 28 men compete the same work.
Answers
Answered by
6
Answer:
52x=35×28
x=35×28
52
x=980
52
x=18.846153846
Answered by
21
Solution
Let 28 men do the same work in x days.
Therefore we have,
Number of men = 52 , 28
Days = 35 , x
Clearly, as the number of men decreases, the number of days will increase.
So, it is a case of inverse variation.
= 28 men will do the work in 65 days.
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