Math, asked by SAmanS, 1 year ago

if 52 men can do a piece of work in 35 days. In how many days will 28 men compete the same work.​

Answers

Answered by intelligency08
6

Answer:

52x=35×28

x=35×28

52

x=980

52

x=18.846153846

Answered by Anonymous
21

Solution

Let 28 men do the same work in x days.

Therefore we have,

Number of men = 52 , 28

Days = 35 , x

Clearly, as the number of men decreases, the number of days will increase.

So, it is a case of inverse variation.

hence \:  \:  \: 52 \times 35 = 28 \times x

x =  \frac{52 \times 35}{28}

x = 65

= 28 men will do the work in 65 days.

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