If 520 mangoes can be bought for 600 rupees, how many can be bought for 1500 rupees?
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Hey mate !
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For Rs 600 , no of mangoes bought = 520
For Re 1 , no of mango bought = 520/600
For Rs 1500 , no of mangoes bought
![= > \frac{520}{6 \cancel{00}} \times 15 \cancel{00} = > \frac{520}{6 \cancel{00}} \times 15 \cancel{00}](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5Cfrac%7B520%7D%7B6++%5Ccancel%7B00%7D%7D++%5Ctimes+15+%5Ccancel%7B00%7D)
=> 260 Ć 5
=> 1300
Therefore,
1300 mangoes can be bought for 1500 rupees.
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Thanks for the question !
___________________
For Rs 600 , no of mangoes bought = 520
For Re 1 , no of mango bought = 520/600
For Rs 1500 , no of mangoes bought
=> 260 Ć 5
=> 1300
Therefore,
1300 mangoes can be bought for 1500 rupees.
_____________________
Thanks for the question !
MsQueen:
Thanks :)
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