Question

If 52272=p^2*q^3*r^4 where p,q and r are prime numbers,then the value of (2p+q-r) is

Answer 1

Step-by-step explanation:

52272=p^2*q^3*r^4

11^2*3^3*2^4=p^2*q^3*r^4

Hence, p=11, q=3, r=2

(2p+q-r)=2*11+3-2

= 22+3-2

=23