Question

if 52gm of a liquid is heated in a vessel from 0°cto 100°c .4gm of the liquid expelled.If 208gm of the same liquid taken in same vesseland heated from 0°c to 50°c. Then the mass in gm of the liquid expelled is​

Answer 1

Answer:

4gms

Explanation:

m2-m1/m1(t2-t1) =m2-m1/m1(t2-t1)

4/52=m2-m1/208

m2-m1=4gms

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