if 54 persons can complete 3/8 th part of a task in 36 days then how many more persons are required to complete 2/3rd part of the same task in 48 days.
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Given :- if 54 persons can complete 3/8 th part of a task in 36 days then how many more persons are required to complete 2/3rd part of the same task in 48 days. ?
Solution :-
given that,
- M1 = 54 persons.
- D1 = 36 days.
- W1 = (3/8) part of a task .
- M2 = Let x .
- D2 = 48 days.
- W2 = (2/3) part of same task.
we know that, If M1 men can do W1 work in D1 days and M2 men can do W2 work in D2 days , then
- (M1 * D1) / W1 = (M2 * D2) / W2
- work ∝ 1/days.
Putting all values we get,
→ (54 * 36) / (3/8) = (x * 48) / (2/3)
→ 54 * 36 * (2/3) = 48x * (3/8)
→ 54 * 12 * 2 = 6x * 3
→ 54 * 12 * 2 = 18x
dividing both sides by 18,
→ 3 * 12 * 2 = x
→ x = 72 persons.
Therefore,
→ Extra persons needed = 72 - 54 = 18 persons (Ans.)
Hence, 18 more persons need to complete the task in given time.
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